- [Instructor] We're going to create three forms of loading.
A force distributed over a bearing face
is a constant pressure.
A force distributed over a bearing face
is a sign of soidal variation in pressure.
And an inertial load applied to the body of the cone rod.
Let's select the little end view.
The first load we're going to create
is the compressive force.
Right Mouse click on the external loads icon
in the Analysis feature tree.
Again, there are a large number of loading options.
The first one we will use is, force.
Select the two right hand services we created previously.
These are in a 120 degree arc.
Make sure the units set is English IPS.
Make sure the radio button's checked for normal loading.
This ensures that we apply a pressure
rather than attraction and we input the force
as 26430 and it's a pound force.
We check the total radio button
to make sure that we apply this value
as a total force across both services.
This button is quite important because
if we didn't select it, we would apply
26430 pounds force to both services
and that's double the amount of load going in.
Now we check okay, hover over the force name
and change it to compression load.
Notice how the total force value
stays appended for name, that's
very useful as a cross check.
I used the force loading option here,
because I had that as my input data.
If I had been supplied with the
equivalent pressure distribution,
then I could have used the pressure loading option instead.
Let's right mouse click on the external load icon,
choose to see that in the menu as the pressure option.
The second load we'll create is
the 180 degree bearing load under the tensile low case.
So here and the menu we're going to choose, bearing load.
Select the two faces on the left
hand side of the little hand.
Click in the coordinate system dialog box,
and then choose from the geometry, tree view,
the little hand coordinate system.
Make sure the units are set as english IPS
and the force, we're going to put in is, 14300 pound force.
Click reverse direction and now the load's
being applied in the right sense.
Make sure the radio button for sinusoidal
distribution is clicked and then click okay.
Hover over the bearing load name
and change it to tension load.
Again, the total force is appended
to the name, it's very useful.
Finally, we'll apply the inertia load,
which is developed axially along the con rod.
Let's select the standard view,
right mouse click on the external loads
and this time we'll select gravity.
This slow type description is a bit misleading
because we normally think of gravity
as being applied vertically downwards
with the same value of 386.4 inches per second squared.
In fact, this is a general inertia set up form
where we can control the direction
and the magnitude of the acceleration.
In the first dialog box, for acceleration direction,
the sense is normal to a plane that we pick.
Select the right plane from the geometry feature manager.
We can see the plane indicated
on the direction of the acceleration of the direction.
We want our acceleration in the negative x direction,
so we check the reverse direction if needed.
We're okay here, acceleration is
pointing the right direction.
Acceleration that cone rod sees is 500g,
but we have to be very careful
with that in fundamental units of inch per second squared.
So we can change the value of acceleration to 500
and the value I use for acceleration
due to gravity is 386.4 inches per second squared.
and a really neat feature of the dialog box
is that we can actually type in this expression
and it will be evaluated, so check okay.
We can see in the name here, regarding
the total of 193,200 inches per second squared
and click on the name and change it to axial acceleration.
I mentioned earlier that solid works expects
the weight density to be defined in the material property.
In our case, that was .284 pounds force per inch squared.
Strictly speaking, we should be
following Newton's second law
and applying force = mass times acceleration
and mass is weight divided by gravity.
Solid Works Simulation presumably
corrects for this by dividing the weight calculated
by the acceleration due to gravity.
And all other FVA solvers I'm aware of,
we need to explicitly define mass
and density using strict mass units.
Be careful to double check the
initial loads that are developed,
we will be doing this later on.